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Parse Error At End Of Input C Program

Search Engine Optimisation provided by DragonByte SEO v2.0.32 (Pro) - vBulletin Mods & Addons Copyright © 2016 DragonByte Technologies Ltd. Is this alternate history plausible? (Hard Sci-Fi, Realistic History) Reduce function is not showing all the roots of a transcendental equation Fill in the Minesweeper clues How do I "Install" Linux? parse error before `...' syntax error These error messages occur when the compiler encounters unexpected input, i.e. I am using the DJGPP compiler. have a peek here

It can be caused by failing to include a header file, or otherwise forgetting to provide a function prototype. Notice that the error refers to line 6, but the error is actually on the previous line. More often, this warning is the result of using a pointer without dereferencing it (e.g. Why is AT&T's stock price declining, during the days that they announced the acquisition of Time Warner inc.? http://stackoverflow.com/questions/5428260/parse-error-at-end-of-input-but-im-sure-my-brackets-are-correct-in-c

Getting started with C or C++ | C Tutorial | C++ Tutorial | C and C++ FAQ | Get a compiler | Fixes for common problems Thread: Parse error at end Warning: this will produce a very large file, which you should cut down to the smallest thing you can manage that still causes the problem. This if-else statement serves this functionality, by getting the remainder of the ascii code, storing it in the array and then dividing the int ascii by two */ if((ascii%2)==0) { binary[total]

This has the effect of masking your global variables so when you input to word you are inputting into the local definitions. Creating a game, from start to finish Recent additions How to create a shared library on Linux with GCC - December 30, 2011 Enum classes and nullptr in C++11 - The time now is 05:39 PM. In particular, the stream stdout is not required to be a constant by the C standard (although on some systems it is a constant).

At least I found the problem. Thanks again! asked 5 years ago viewed 2473 times active 5 years ago Get the weekly newsletter! http://cboard.cprogramming.com/cplusplus-programming/18979-parse-error-end-input.html Post your question and get tips & solutions from a community of 418,616 IT Pros & Developers.

Sure, give us something to look at (we can't read minds) or start "cutting out" large chunks of the file with #if / #endif until the error goes away. If i write code at line 50, then the error occurs at line 51. But that's ok. This error occurs if a non-constant value is used.

Here is my code. http://crasseux.com/books/ctutorial/parse-error-at....html Forum Today's Posts C and C++ FAQ Forum Actions Mark Forums Read Quick Links View Forum Leaders What's New? warning: unused variable `...' warning: unused parameter `...' These warnings indicate that a variable has been declared as a local variable or in the parameters of a function, but has not Functions declared void do not need return statements.

Example: #include int main (void) { printf ("Hello World!\n); /* no closing quote */ return 0; } The opening quote for the string in this program does not have a navigate here Example: #include int main (void) { printf ("Hello ") /* missing semicolon */ printf ("World!\n"); return 0; } There is a missing semicolon after the first call to printf, giving warning: passing arg of ... No No return 0; is included in else. ..

However, the definition of the struct is needed before the pointer can be dereferenced to access individual members. writing int i = p instead of int i = *p). Is this parse error indicative of anything particular? Check This Out Note that non-constant initializers are allowed in C++. <<< previous table of contents next >>> Published under the terms of the GNU General Public License Design by

warning: control reaches end of non-void function A function which has been declared with a return type, such as int or double, should always have a return statement returning a value The operator '=' both assigns and returns the value of its right-hand side, causing the variable i to be modified and the unexpected branch taken. It's quick & easy.

Could someone point out my silly little mistake for me? :) #include #include "/user/cse320/Projects/project06.support.h" #include "/user/cse320/Projects/project06.hardware.h" void execute() { unsigned long int IRdecode; IRdecode = IR; IRdecode >> 30; if

Of course you need to be smart about placement of the if/endif directives. -- - Mark -> -- Nov 14 '05 #2 P: n/a Bill Potter Some times it happends that All rights reserved. initializer element is not a constant In C, global variables can only be initialized with constants, such as numeric values, NULL or fixed strings. quaere et invenies. "Simplicity does not precede complexity, but follows it." -- Alan Perlis "Testing can only prove the presence of bugs, not their absence." -- Edsger Dijkstra "The only real

Originally posted by erikcn No No return 0; is included in else. Register Remember Me? All rights reserved. this contact form This may indicate that you began more blocks with { than you closed with }. -- Ben Pfaff email: bl*@cs.stanford.edu web: http://benpfaff.org Nov 14 '05 #4 P: n/a John Hanley >

a blank screen, yet the php error logis empty How to parse a file in C++ Parse error: parse error, expecting `T_STRING' or `T_VARIABLE' or `T_NUM_STRING' Incorrect values when using float.Parse(string) It is frequently caused by a missing semicolon. Since you're using the standard C fopen() which deals in FILE*s, you'll want to use the corresponding fclose() which also uses FILE*s. warning: suggest parentheses around assignment used as truth value This warning highlights a potentially serious error, using the assignment operator '=' instead of the comparison operator '==' in the test of

Example: #include int main (void) { printf ('Hello World!\n'); /* wrong quotes */ return 0; } The program above confuses single-quotes and double-quotes. warning: unknown escape sequence `...' This error is caused by an incorrect use of the escape character in a string. Note that according to the C standard there is no limit on the length of a character constant, but the value of a character constant that contains more than one character Do I need to do this?

An unused variable can be the result of a programming error, such as accidentally using the name of a different variable in place of the intended one. This error occurs if single quotes are used to enclose more than one character. I did that and by the way thanx for that because knowing that may save e a lot of problems in the future. The option -Wconversion is needed to enable this warning.

sumthing? 06-02-2002 #2 Traveller View Profile View Forum Posts Registered User Join Date May 2002 Posts 317 This is what I noticed right off: Code: char word[502]; int decimal[502]; void binary(); Join them; it only takes a minute: Sign up “parse error at end of input”, but I'm sure my brackets are correct. (in C) up vote 0 down vote favorite I'm Data accessed through a pointer marked as const should not be modified, and the pointer itself can only be assigned to other pointers that are also marked const. dwk Seek and ye shall find.